(3x-4)(3x+4)=9x^2-16

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Solution for (3x-4)(3x+4)=9x^2-16 equation: 


Simplifying
(3x + -4)(3x + 4) = 9x2 + -16

Reorder the terms:
(-4 + 3x)(3x + 4) = 9x2 + -16

Reorder the terms:
(-4 + 3x)(4 + 3x) = 9x2 + -16

Multiply (-4 + 3x) * (4 + 3x)
(-4(4 + 3x) + 3x * (4 + 3x)) = 9x2 + -16
((4 * -4 + 3x * -4) + 3x * (4 + 3x)) = 9x2 + -16
((-16 + -12x) + 3x * (4 + 3x)) = 9x2 + -16
(-16 + -12x + (4 * 3x + 3x * 3x)) = 9x2 + -16
(-16 + -12x + (12x + 9x2)) = 9x2 + -16

Combine like terms: -12x + 12x = 0
(-16 + 0 + 9x2) = 9x2 + -16
(-16 + 9x2) = 9x2 + -16

Reorder the terms:
-16 + 9x2 = -16 + 9x2

Add '16' to each side of the equation.
-16 + 16 + 9x2 = -16 + 16 + 9x2

Combine like terms: -16 + 16 = 0
0 + 9x2 = -16 + 16 + 9x2
9x2 = -16 + 16 + 9x2

Combine like terms: -16 + 16 = 0
9x2 = 0 + 9x2
9x2 = 9x2

Add '-9x2' to each side of the equation.
9x2 + -9x2 = 9x2 + -9x2

Combine like terms: 9x2 + -9x2 = 0
0 = 9x2 + -9x2

Combine like terms: 9x2 + -9x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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